下面是一个 Oracle PL/SQL 函数：

CREATE OR REPLACE FUNCTION cs_fmt_browser_version(v_name IN varchar, v_version IN varchar)
RETURN varchar IS
BEGIN
    IF v_version IS NULL THEN
        RETURN v_name;
    END IF;
    RETURN v_name || '/' || v_version;
END;
/
show errors;

让我们过一遍这个函数，看看它与 PL/pgSQL 的差异：

这个函数移植到 PostgreSQL 后是这个样子：

CREATE OR REPLACE FUNCTION cs_fmt_browser_version(varchar, varchar)
RETURNS varchar AS '
DECLARE
    v_name ALIAS FOR $1;
    v_version ALIAS FOR $2;
BEGIN
    IF v_version IS NULL THEN
        return v_name;
    END IF;
    RETURN v_name || ''/'' || v_version;
END;
' LANGUAGE plpgsql;

下面的过程从 SELECT 语句抓取行，并把结果用 IF 语句构造成一个大函数，以求高效。请特别注意游标和 FOR 循环中的差异，

这是 Oracle 版本：

CREATE OR REPLACE PROCEDURE cs_update_referrer_type_proc IS
    CURSOR referrer_keys IS 
        SELECT * FROM cs_referrer_keys 
        ORDER BY try_order;

    a_output VARCHAR(4000); 
BEGIN 
    a_output := 'CREATE OR REPLACE FUNCTION cs_find_referrer_type(v_host IN VARCHAR, v_domain IN VARCHAR, 
v_url IN VARCHAR) RETURN VARCHAR IS BEGIN'; 

    FOR referrer_key IN referrer_keys LOOP 
        a_output := a_output || ' IF v_' || referrer_key.kind || ' LIKE ''' || 
referrer_key.key_string || ''' THEN RETURN ''' || referrer_key.referrer_type || 
'''; END IF;'; 
    END LOOP; 

    a_output := a_output || ' RETURN NULL; END;'; 
    EXECUTE IMMEDIATE a_output; 
END; 
/ 
show errors;

下面是这个函数在 PostgreSQL 中的最终样子：

CREATE FUNCTION cs_update_referrer_type_proc() RETURNS integer AS '
DECLARE
    referrer_keys RECORD;  -- Declare a generic record to be used in a FOR
    a_output varchar(4000);
BEGIN 
    a_output := ''CREATE FUNCTION cs_find_referrer_type(varchar, varchar, varchar) 
                  RETURNS varchar AS '''' 
                     DECLARE 
                         v_host ALIAS FOR $1; 
                         v_domain ALIAS FOR $2; 
                         v_url ALIAS FOR $3;
                     BEGIN ''; 

    -- Notice how we scan through the results of a query in a FOR loop
    -- using the FOR <record> construct.

    FOR referrer_keys IN SELECT * FROM cs_referrer_keys ORDER BY try_order LOOP
        a_output := a_output || '' IF v_'' || referrer_keys.kind || '' LIKE '''''''''' 
                 || referrer_keys.key_string || '''''''''' THEN RETURN '''''' 
                 || referrer_keys.referrer_type || ''''''; END IF;''; 
    END LOOP; 
  
    a_output := a_output || '' RETURN NULL; END; '''' LANGUAGE plpgsql;''; 
 
    -- EXECUTE will work because we are not substituting any variables.
    -- Otherwise it would fail.  Look at PERFORM for another way to run functions.
    
    EXECUTE a_output; 
END; 
' LANGUAGE plpgsql;

下面的 Oracle PL/SQL 过程用于解析 URL 并返回若干元素（主机、路径和查询）。 PL/pgSQL 函数只能返回一个值。在 PostgreSQL 中，绕过这个问题的一种办法是把过程拆成三个不同的函数：一个返回主机，一个返回路径，一个返回查询。

这是 Oracle 版本：

CREATE OR REPLACE PROCEDURE cs_parse_url(
    v_url IN VARCHAR,
    v_host OUT VARCHAR,  -- This will be passed back
    v_path OUT VARCHAR,  -- This one too
    v_query OUT VARCHAR) -- And this one
IS
    a_pos1 INTEGER;
    a_pos2 INTEGER;
BEGIN
    v_host := NULL;
    v_path := NULL;
    v_query := NULL;
    a_pos1 := instr(v_url, '//');

    IF a_pos1 = 0 THEN
        RETURN;
    END IF;
    a_pos2 := instr(v_url, '/', a_pos1 + 2);
    IF a_pos2 = 0 THEN
        v_host := substr(v_url, a_pos1 + 2);
        v_path := '/';
        RETURN;
    END IF;

    v_host := substr(v_url, a_pos1 + 2, a_pos2 - a_pos1 - 2);
    a_pos1 := instr(v_url, '?', a_pos2 + 1);

    IF a_pos1 = 0 THEN
        v_path := substr(v_url, a_pos2);
        RETURN;
    END IF;

    v_path := substr(v_url, a_pos2, a_pos1 - a_pos2);
    v_query := substr(v_url, a_pos1 + 1);
END;
/
show errors;

下面是返回主机部分的 PL/pgSQL 函数可能的样子：

CREATE OR REPLACE FUNCTION cs_parse_url_host(varchar) RETURNS varchar AS '
DECLARE
    v_url ALIAS FOR $1;
    v_host varchar;
    v_path varchar;
    a_pos1 integer;
    a_pos2 integer;
    a_pos3 integer;
BEGIN 
    v_host := NULL; 
    a_pos1 := instr(v_url, ''//'');

    IF a_pos1 = 0 THEN 
        RETURN '''';  -- Return a blank
    END IF; 

    a_pos2 := instr(v_url,''/'',a_pos1 + 2);
    IF a_pos2 = 0 THEN 
        v_host := substr(v_url, a_pos1 + 2); 
        v_path := ''/''; 
        RETURN v_host; 
    END IF; 

    v_host := substr(v_url, a_pos1 + 2, a_pos2 - a_pos1 - 2 ); 
    RETURN v_host; 
END; 
' LANGUAGE plpgsql;

Oracle 版本：

CREATE OR REPLACE PROCEDURE cs_create_job(v_job_id IN INTEGER) IS
    a_running_job_count INTEGER;
    PRAGMA AUTONOMOUS_TRANSACTION;(1)
BEGIN
    LOCK TABLE cs_jobs IN EXCLUSIVE MODE;(2)

    SELECT count(*) INTO a_running_job_count FROM cs_jobs WHERE end_stamp IS NULL;

    IF a_running_job_count > 0 THEN
        COMMIT; -- free lock(3)
        raise_application_error(-20000, 'Unable to create a new job: a job is currently running.');
    END IF;

    DELETE FROM cs_active_job;
    INSERT INTO cs_active_job(job_id) VALUES (v_job_id);

    BEGIN
        INSERT INTO cs_jobs (job_id, start_stamp) VALUES (v_job_id, sysdate);
        EXCEPTION WHEN dup_val_on_index THEN NULL; -- don't worry if it already exists(4)
    END;
    COMMIT;
END;
/
show errors

这样的过程可以很容易地转换为返回 integer 的 PostgreSQL 函数。这个过程特别有意思，因为它能教给我们一些东西：

下面是我们把这个过程移植到 PL/pgSQL 的样子：

CREATE OR REPLACE FUNCTION cs_create_job(integer) RETURNS integer AS '
DECLARE
    v_job_id ALIAS FOR $1;
    a_running_job_count integer;
    a_num integer;
BEGIN
    LOCK TABLE cs_jobs IN EXCLUSIVE MODE;
    SELECT count(*) INTO a_running_job_count FROM cs_jobs WHERE end_stamp IS NULL;

    IF a_running_job_count > 0
    THEN
        RAISE EXCEPTION ''Unable to create a new job: a job is currently running.'';
    END IF;

    DELETE FROM cs_active_job;
    INSERT INTO cs_active_job(job_id) VALUES (v_job_id);

    SELECT count(*) INTO a_num FROM cs_jobs WHERE job_id=v_job_id;
    IF NOT FOUND THEN  -- If nothing was returned in the last query
        -- This job is not in the table so lets insert it.
        INSERT INTO cs_jobs(job_id, start_stamp) VALUES (v_job_id, current_timestamp);
        RETURN 1;
    ELSE
        RAISE NOTICE ''Job already running.'';(1)
    END IF;

    RETURN 0;
END;
' LANGUAGE plpgsql;